高级pos函数

     阅读 973 次    更新时间:2014/4/20    

function PosEx(const SubStr, S: string; Offset: Cardinal = 1): Integer;
var
  I,X: Integer;
  Len, LenSubStr: Integer;
begin
  if Offset = 1 then
    Result := Pos(SubStr, S)
  else
  begin
    I := Offset;
    LenSubStr := Length(SubStr);
    Len := Length(S) - LenSubStr + 1;
    while I <= Len do
    begin
      if S[I] = SubStr[1] then
      begin
        X := 1;
        while (X < LenSubStr) and (S[I + X] = SubStr[X + 1]) do
          Inc(X);
        if (X = LenSubStr) then
        begin
          Result := I;
          exit;
        end;
      end;
      Inc(I);
    end;
    Result := 0;
  end;
end;
 
 

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